subtract (x^2-y^2) from (2x^2-3y^2+6xy)
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2x² - 3y² + 6xy - (x² - y²)
=> 2x² - 3y² + 6xy - x² + y²
=> 2x² - x² - 3y² + y² + 6xy
=> x² - 2y² + 6xy
=> 2x² - 3y² + 6xy - x² + y²
=> 2x² - x² - 3y² + y² + 6xy
=> x² - 2y² + 6xy
Answered by
0
Answer: x² - 2y² + 6xy
To subtract an algebraic expression, follow these steps:
1. Look for similar terms throughout an expression.
2. Determine the difference between all terms' numerical coefficients.
3. Type the necessary difference.
Step-by-step explanation:
2x² - 3y² + 6xy - (x² - y²)
=> 2x² - 3y² + 6xy - x² + y²
=> 2x² - x² - 3y² + y² + 6xy
=> x² - 2y² + 6xy
To learn more about algebraic from the given link
https://brainly.in/question/54168933
To learn more about coefficients from the given link
https://brainly.com/question/1038771
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