Subtract x –2y from the sum of -3x + 5y -3z and2x -7y + 3z
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Answer:
at first sum of - 3x + 5y -3z + (2x-7y+3z)=
-3x+5y-3z+2x-7y+3z
= -3x+2x+5y-7y-3z+3z
= -x-2y
now -x-2y+ (x-2y)
= -x-2y+x-2y
= -x+x-2y-2y
= -4y
Answered by
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answer:
sum of -3x + 5y -3z and2x -7y + 3z
= -3x + 5y -3z + 2x -7y + 3z
= - 3x + 2x + 5y - 7y -3z + 3z
= -x - 2y
now
subtract x –2y from -x - 2y
= - x - 2y - ( x- 2y )
= -x -2y -x + 2y
= -x - x - 2y + 2y
= - 2x ( ans)
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