subtract x^3 + 2x^2y + 6xy^2 - ^3 from 2^3 - 6xy^2 - 4x^2 - 2x^3
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Answer:
Step-by-step explanation:
The equation can be written as
4.2
2x
−2
x
⋅3
x
−18.3
2x
=0
Dividing by 2
x
⋅3
x
,we get
4(
3
2
)
x
−1−18(
3
2
)
x
=0
Put (
3
2
)
x
=t. Then
t
4
−1−18t=0
or 18t
2
+t−4=0 or (2t+1)(9t−4)=0
∴t=
9
4
or
2
−1
∴t=(
2
3
)
x
=(
9
4
)=(
3
2
)
2
=(
2
3
)
−2
giving x=−2
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