Math, asked by aadityathakur5304267, 4 months ago

Subtract x 3 + 4 x 2 y + 7 x y 2 - y 2 from y 2 – 6 x y 2 – 3 x 2 y .​

Answers

Answered by iqrasadafnaaz
1

Answer:

= x^3 + 4x^2y + 7xy^2 - y^2 - ( y^2-6xy^2-3x^2y )

= x^3 + 4x^2y + 7xy^2 - y^2 - y^2 + 7xy^2 + 3x^2y

= x^3 + (4x^2y+3x^2y) + (7xy^2+7xy^2) - (y^2- y^2)

= x^3 + 7x^2y + 14xy^2- 2y^2

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