Question

Subtract (x-3y-z) from the sum of (2x-y+z) and (x+y-4z).​

Answer 1

Answer:

ok

Step-by-step explanation:

sum of (2x-y+z) and (x+y-4z)

= 2x-y+z+x+y-4z

= 3x-3z

now, subtract (3x-3z) - (x-3y-z)

=. 3x-3z-x+3y+z

= 2x+3y-2z

Answer 2

Answer:

(x+3y−4z)+(2x+y−z)+(−2x+3y−z)−(2x−4y+3z)

=(x+2x+3y+y−4z−z)+(−2x+3y−z)−(2z−4y+3z)

=(3x+4y−5z)+(−2x+3y−z)−(2x−4y+3z)

=(x+7y−6z)−(2x−4y+3z)

=x−2x+7y+4y−6z−3z

=−x+11y−9z

∴ Ans :−(−x+11y−9z)

hope this ans will help you dear...