subtract
x-4xy+z and 2xy+2x-4z from the sum of -6+4zand -18z
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Answer:
-3x+2xy-11z-6
Step-by-step explanation:
x-4xy+z = a(let)
2xy+2x-4z = b(let)
-6+4z = c(let)
-18z = d(let)
A/Q
ans= (c+d)-(a+b)
(-6+4z-18z) - (x-4xy+z+2xy+2x-4z)
=(-6-14z) - (3x-2xy-3z)
= -6-14z - 3x+2xy+3z
= -3x+2xy-11z-6
hope it helps❤
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