subtract x square + x + 1 from the sum of 5x square - 7x + 4 and -3x square+ 5x + 2
Answers
Answered by
0
Answer:
Step-by-step explanation:
The sum of ( 5x² - 7x + 4 ) and ( - 3x² + 5x + 2 )
( 5x² - 7x + 4 ) + ( - 3x² + 5x + 2 )
= 5x² - 7x + 4 - 3x² + 5x + 2 ( ∵ + × - = )
= ( 5x² - 3x² ) + ( - 7x + 5x ) + ( 4 + 2 ) ( ∵ like terms adding )
= 2x² + ( - 2x ) + 6
= 2x² - 2x + 6 .
Now subtract ( x² + x + 1 ) from ( 2x² - 2x + 6 )
= ( 2x² - 2x + 6 ) - ( x² + x + 1 )
= 2x² - 2x + 6 - x² - x - 1 ( ∵ - × + = - )
= ( 2x² - x² ) + ( - 2x - x ) + ( 6 - 1 ) ( ∵ like terms )
= x² + ( - 3x ) + 5
= x² - 3x + 5 is the answer. (∵ + × - = - )
Similar questions