subtract [ x-y+3z] from [ 2z-3y+2x ]
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2
Answer:
[2z-3y+2x] - [x-y+3z]
2z-3y+2x-x+y-3z
2z-3z-3y+y+2x-x
-z-4y-x
Answered by
13
[2z-3y+2x] - [x-y+3z]
2z-3y+2x-x+y-3z
2z-3z-3y+y+2x-x
-z-4y-x
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