Math, asked by chirag178, 1 year ago

subtract (x2 -y2)from (2x2-3y2+6xy)

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Answers

Answered by anuritha
36
2x^2-3y^2+6xy-(x^2-y^2)
(2x^2-x^2)+(-3y^2+y^2)+6xy 
x^2-3y^2+6xy

anuritha: hope it helps
Answered by naasideas
5

Answer:

Step-by-step explanation:

2x^2-3y^2+6xy-(x^2-y^2)

(2x^2-x^2)+(-3y^2+y^2)+6xy  

x^2-3y^2+6xy

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