Math, asked by daminimahajan619, 4 months ago

Subtract: x2y−4/5xy2+4/3xy from 2/3x2y+3/2xy2−1/3xy

Answers

Answered by vaityrohan064

Step-by-step explanation:

(i) x3- 2x2y + 3xy2- y3+ 2x3- 5xy2 + 3x2y- 4y3 ... 3x 3 + x2y - 2xy2 - 5y3 ... (iv) x3 − 5x2 + 3x + 1, take away 6x2 − 4x3 + 5 + 3x ... x - 3x - 2y - 5y + 3z + 7

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Subtract: x2y−4/5xy2+4/3xy from 2/3x2y+3/2xy2−1/3xy​

Answers

Subtract: x2y−4/5xy2+4/3xy from 2/3x2y+3/2xy2−1/3xy