Subtract x³-2xy²+4x²y-y³ from y³+2x³-3xy³+3x²y
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Step by step explanation :
= y³+2x³-3xy³+3x²y-(x³-2xy²+4x²y-y³)
= y³+2x³-3xy³+3x²y-x³+2xy²-4x²y+y³
= y³+y³+2x³-x³-3xy³+2xy²+3x²y-4x²y
= 2y³+x³-3xy³+2xy²-1x²y
Answer is = 2y³+x³-3xy³+2xy²-1x²y
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