subtract x³-2xy²+5x²y-6 from x³+3x²y+3xy²-2. please answer me it is urgent
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The subtraction is carried out as follows,
(y3−3xy2−4x2y)−(x3+2x2y+6xy2−y3)
=y3−3xy2−4x2y−x3−2x2y−6xy2+y3
Re-arranging the like terms together,
=(y3+y3)+(−3xy2−6xy2)+(−4x2y−2x2y)−x3
=2y3−9xy2−6x2y−x3
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