Math, asked by dahiyasushil493, 8 months ago

Subtract: [-y3 + 3yz] from [4y2 –3yz + 12]

Answers

Answered by dilliprasaddhakal528

0

[4y2 –3yz + 12] - [-y3 + 3yz]

= 4y2 –3yz + 12+y³-3yz

= 4y² -6yz+12+y³ Ans.

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