Question

subtracted the sum of 2a-3b+c and a-b-c from the sum of the sum of 3a-4b and 3a-4b and 3a - 4b+c ​

Answer 1

Answer:

Explanation:

- ( 2a-3b+c + (a-b-c) )

+ (3a-4b + (3a-4b+c) )

= -2a + 3b- c - a + b + c

+ ( 3a-4b+3a-4b+c)

= -3a + 4b + ( 6a - 8b + c)

= -3a + 4b + 6a - 8b + c

= 3a - 4b + c