Question

subtracted the sum of 3x²-6+5x and 2x+5-7x² from the sum of x²+2x+9 and -2x²-11+12x. please solve it is urgent please ​

Answer 1

Answer:

-3x²+7x-1

Step-by-step explanation:

Given,

p(x)= 3x²-6+5x

= 3x²+5x-6

q(x)= 2x+5-7x²

= -7x²+2x+5

r(x)= x²+2x+9

= x²+2x+9

s(x)= -2x²-11+12x

= -2x²+12-11

Solution,

Step: 1

p(x)+q(x)

=> (3x²+5x-6) + (-7x²+2x+5)

=> -4x²+7x-1 •••••••••• 《1》

Step: 2

r(x)+s(x)

=> (x²+2x+9) + (-2x²+12-11)

=> -x²+14x-2 ••••••••••《2》

Step: 3

Subtract 《1》from《2》

=> (-x²+14x-2) - (-4x²+7x-1)

=> (-x²+14x-2) - (4x²-7x+1)

=> -3x²+7x-1

Therefore, (x²+2x+9)+(-2x²+12-11) - (3x²+5x-6)+(-7x²+2x+5)= -3x²+7x-1