Question

subtracted the sum of a² + ab+6b² and -5a²+3b² from the sum of —3a²—6ab and 4a² + 5b²— 2ab​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Given

(-3a^2 - 6ab) + (4a^2 + 5b^2 - 2ab) - (a^2 + ab + 6b^2) + (-5a^2 + 3b^2)

Solution

(a^2 - 8ab + 5b^2) - (-4a^2 + ab + 9b^2)

a^2 - 8ab + 5b^2 + 4a^2 - ab - 9b^2

= 5a^2 - 9ab - 4b^2

Answer 2

Answer:

$5 {a}^{2} - 4 {b}^{2} - 9ab$

Step-by-step explanation:

$( - 3 {a}^{2} - 6ab) + (4 {a }^{2} + 5 {b}^{2} - 2ab) -( ( {a}^{2} + ab + 6 {b}^{2} ) + ( - 5 {a}^{2} + 3 {b}^{2} )) \\ ( {a}^{2} + 5 {b}^{2} - 8ab) - ( { - 4a}^{2} + 9 {b}^{2} + ab) \\ {a}^{2} + 5 {b}^{2} - 8ab + 4 {a}^{2} - 9 {b}^{2} - ab) \\ (5 {a}^{2} - 4 {b}^{2} - 9ab)$