Subtracting x 2 - y 2 + z2 from x2 - y 2 - z 2 , the resultant expression is _______ (2x 2 ,2y 2 , -2z 2 ,૦)
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what is the question?
Step-by-step explanation:
Let the digit at unit's place be y and the digit at ten's place be x.
So, the number will be 10x+y
According to the first condition-
⇒x+y=9 ....(1)
According to the second condition-
⇒10y+x=10x+y+27⇒9y=9x+27
⇒y=x+3 ...(2)
Put the value of y in (2), we have
⇒x+x+3=9
⇒x=3
⇒x+y=9
⇒3+y=9
⇒y=6
∴ the number is 36.
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