subtraction: (1)= 5a²-7ab+5b² from 3ab-2a²-2b²
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3ab – 2a² – 2b² - (5a² – 7ab + 5b²)
(while subtracting we must change the sign of second term)
=3ab – 2a² – 2b² - 5a² + 7ab - 5b²
=3ab + 7ab – 2a² - 5a²– 2b²- 5b²
= 10ab - 7a² - 7b²
Thanks
(while subtracting we must change the sign of second term)
=3ab – 2a² – 2b² - 5a² + 7ab - 5b²
=3ab + 7ab – 2a² - 5a²– 2b²- 5b²
= 10ab - 7a² - 7b²
Thanks
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