Succsesive ionization energies of an element X are 104KJ,200KJ,420KJ,285KJ Per Mole.Identify group to which the element belong?
Answers
Answered by
4
Given, Successive ionization energies of an element X are 104KJ,200KJ,420KJ,285KJ.
Difference between First and Second Ionization energies is around 100KJ.
Difference between second and third ionization energies is 220 KJ.
This sudden increase in I.E can be because We are trying to remove an electron from stable species.
The rectant species in the third Ionization energy is X^+2.
We can conclude that, The element X when loses 2 electrons is attaining stability. And, Hence removal of 3rd electron is hard.
Thus, The element belongs to 2nd Group in the periodic table.
Similar questions