Question

Sucrose burns in oxygen to form CO2 and H2O according to this equation:
C12H22O11 + 12 O2  12 CO2 + 11 H2O
What volume of CO2 measured at STP is produced from burning 100 g of sucrose?

Answer 1

Answer:

78.59L

Explanation:

C12H22O11 + 12O2 = 12CO2 + 11H2O

1mol 12×22.4L

342g of sucrose = 12×22.4L of CO2 at STP

100g of sucrose =( 12×22.4/342)×100L

= 78.59L