Question

sucrose (molecular weight342)of mass 34.2g was dissolved in 500 ml of a solution .calculate the concentration of the solution in mol /2 and g/l units​

Answer 1

Answer:

4.48atm

Explanation:

Osmotic pressure, π=CRT

Here, C= molar concentration of sucrose solution.

C= molecular weight (in g/mol) of sucrose× volume (in L) of solution  weight (in g) of sucrose

C= 342 g/mol× 1 L 68.4 g

Osmotic pressure,

π= 342 g/mol× 1 L 68.4 g× 0.082 L atm / mol /K× 273 K

π= 4.48 atm.

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Answer 2

Given: Sucrose (molecular weight= 342)of mass 34.2g was dissolved in 500 ml of a solution

To find: Concentration of the solution in mol /L and g/L

Explanation: Given mass of sucrose= 34.2 g

Molecular weight of sucrose= 342 g

Moles of sucrose

= Given mass/ Molecular mass

= 34.2/342

= 0.1 moles

Volume of solution

= 500 mL

= 0.5 L (since 1 L = 1000 mL)

Concentration in mol/L

= Number of moles/ Volume of solution in L

= 0.1 / 0.5

= 0.2 mol/L

Concentration in g/L

= Given mass in grams/Volume of solution in L

= 34.2/ 0.5

= 68.4 g/L

Therefore, the concentration of the solution is 0.2 mol/L and 68.4 g/L.