Question

Sudesh is twice as old as Seema. If 6 years is subtracted from Seema's age and four years are added to sudesh's age,Sudesh will be four times Seema's age. How old were they three years ago?​

Answer 1

Answer:

Step-by-step explanation:

Lets Seema's age be x

Sudesh's age = 2x

4(x - 6) = 2x + 4

4x - 24 = 2x + 4

2x = 28

x = 14

Therefore

Present age of Seema = 14 years

Present age of Sudesh = 28 years

Age of Seema 3 years ago = 11 years

Age of Sudesh 3 years ago = 25 years

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• After 3 years ago Seema's age = 11 years
• And, after 3 years ago Sudesh's age = 25 years

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$\sf{\underline{\green{Given:-}}}$

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• Sudesh is twice as old as Seema. If 6 years is subtracted from Seema's age and four years are added to sudesh's age,Sudesh will be four times Seema's age.

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$\sf{\underline{\green{Find:-}}}$

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• After 3 years ago Seema's age = ?
• After 3 years ago Sudesh's age = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let the age of Seema be y

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• Sudesh's age = 2y

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {4(y - 6) = 2y + 4}$

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$\longrightarrow \sf {4y - 24 + 2y + 4}$

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$\longrightarrow \sf {4y - 2y = 24 + 4 }$

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$\longrightarrow \sf {2y = 28 }$

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$\longrightarrow \sf {y = 14}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• Present age of Seema is 14 years.

• Present age of Sudesh = 2 × 14
• Present age of Sudesh = 28 years

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$\:\:\:\:\dag\bf{\underline{\underline \red{After\:3\: years\:ago:-}}}$

• Age of Seema = 14 - 3
• Age of Seema = 11 years

• Age of Sudesh = 28 - 3
• Age of Sudesh = 25 years

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$\rule{200}{2}$