Math, asked by hinanahi, 1 year ago

Sudesh is twice as old as Seema if 6 years is subtracted from seema's age and 4 years are added to sudesh 's age,sudesh will be 4 times seema's age how old were the 3 year ago

Answers

Answered by gravitation1
1

x = 2y 

4(y-6) = 4+x 

4y-24 = 4 + 2y 

2y = 28 

y = 14, x = 28 

They were 11 and 25 three years ago.

hinanahi: i can't understand your ans
gravitation1: it's simple use your mind please
hinanahi: sudesh age2y and seema age x am l right
gravitation1: yes
gravitation1: its little hard but i think that you understood that
hinanahi: yes now l am understand
gravitation1: yes i think do you reported it....
hinanahi: thanks
Answered by Anonymous
0

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

  • Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

  • Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.
Similar questions