Question

sudesh is twice as old as seema . if six years are subtracted from seema's age and four years are added to sudesh age ,sudesh will be four times seema age .how old were they 3 years ago

Answer 1

Given :

• Sudesh is twice as old as seema.
• If six years are subtracted from Seema's age and four years are added to Sudesh age, Sudesh will be four times seema age.

To find :

• Their ago before 3 years?

Solution :

☯ Let Present age of Seema be x years,

Then, Present age of Sudesh will be 2x years.

★ According to the Question:

➯ 4(x - 6) = (2x + 4)

➯ 4x - 24 = 2x + 4

➯ 4x - 2x = 4 + 24

➯ 2x = 28

➯ x = 28/2

➯ x = 14

Therefore,

• Present age of Seema, x = 14 years
• Present age of Sudesh, 2x = 28 years

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☯ Now, Their ages before 3 years,

• Age of Seema, (x - 3) = 14 - 3 = 11 years
• Age of Sudesh, (2x - 3) = 28 - 3 = 25 years

∴ Hence, Ages of Seema and Sudesh before 3 years is 11 years and 25 years respectively.

Answer 2

Answer:

Given :-

• Sudesh is twice as Seema
• if six years are subtracted from seema's age and four years are added to sudesh age ,sudesh will be four times seema

To Find :-

Age of both 3 years old

Solution :-

Let the present age of Seema be x years And Sudesh age will be 2x

$\tt \: 4(x - 6) = (2x + 4)$

$\tt \: 4x - 24 = 2x + 4$

$\tt \: 4x - 2x = 24 + 4$

$\tt \: 2x = 24 + 4$

$\tt \: 2x = 28$

$\tt \: x = \dfrac{28}{2}$

$\tt \: x = 14$

Present age of Seema = 14 years

Present age of Sudesh = 28 years

Age of 3 years ago

age of Seema = 14 - 3 = 11

Age of Sudesh = 28 - 3 = 25