sudesh is twice as old as seema. if six years is subtract from seema's age and Four year are added to sudesh's age, sudesh will be four times seema's age. how old were they three year ago
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Answered by
15
let
sudesh age=x
seema age =y
according to question x=2y
and 4(y-6)=x+4
4y-24=x+4
4y-24-x-4=0
4y-24-2y-4=0
2y-28=0
2y=28
y=14=seema age
sudesh age=x=2(14)
=28
therefore seema age =14,sudesh age =28
if it helped mark as brainliest.
sudesh age=x
seema age =y
according to question x=2y
and 4(y-6)=x+4
4y-24=x+4
4y-24-x-4=0
4y-24-2y-4=0
2y-28=0
2y=28
y=14=seema age
sudesh age=x=2(14)
=28
therefore seema age =14,sudesh age =28
if it helped mark as brainliest.
Answered by
5
let the age of seema be x
then sudesh is 2x
ATQ
4(x-6)=2x+4
4x-24=2x+4
2x=28
x=14
seema=14
Sudesh = 28
after three years
seema= 17
sudesh= 31
then sudesh is 2x
ATQ
4(x-6)=2x+4
4x-24=2x+4
2x=28
x=14
seema=14
Sudesh = 28
after three years
seema= 17
sudesh= 31
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