Question

Sudesh is twice as old as seema. If six years is subtracted from seema's age annd four years are added to sudesh's age, sudesh will be four times seema's age . How old were they three years ago?

Answer 1

let sudesh's age is x and sheema's age x/2
a/c to question ,
4 ( x/2 -6)= (x+2)
2x -24 =x + 2
x =26
hence sudesh present age =26
and sheema present age =13
so ,three ago sudesh 's age was 29
and sheema's age was =16

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.