Question

Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they three years ago?​

Answer 1

Answer:

let the age of sudhesh be x

let the age of seema is x+2

so, when we subtract the 6 years from seema's age , we get (

x+2)-6

so,

(4+x)+(x+2)-6=4x+2

4+x+x+2-6=4x+2

4+2x+2-6=4x+2

2x -4x=2-4+6

-2x=4

x=4÷-2

x=2 ans

Answer 2

Step-by-step explanation:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

• Age of Seema = x - 6

• Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.