Question

sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four year are added to sudesh 's age, sudesh will be four time Seema's age. How old they are three years ago?​

Answer 1

$\huge\mathfrak{\underline{\green{Answer:\:Sudhesh : 25; \:Seema\::11}}}$

$\rule{100}2$

$\textbf{\underline{\underline{Step-By-Step\:Explanation:-}}}$

→ Let present age of Seema be ' s ' years.

So, Sudesh will be ' 2s ' years.

Also,

It is stated that,

If 6 years are subtracted from Seema's age and 4 years are added to Sudesh's age, Sudesh will be 4 times of Seema's age, i.e -

4 ( s - 6 ) = 2s + 4 ___________ (!)

Now,

Solve equation ( ! ) to find Seema's present age.

$\sf 4 ( s - 6 ) = 2s + 4 \\\\ \implies 4s - 24 = 2s + 4 \\\\ \implies 4s - 2s = 24 + 4 \\\\ \implies 2s = 28 \\\\ \implies s =\dfrac{28}{2} \\\\ \therefore s = 14$

Hence,

→ Present age of Seema = 14 years.

→ Present age of Sudesh = 28 years.

Now,

To find their 3 years ago ages, subtract 3 from their present ages.

For Seema,

→ 14 - 3 = 11 years.

For Sudesh,

→ 28 - 3 = 25 years.

Answer : $\sf\blue{Seema\:was\:11\:\:and\:Sudesh\:was\:25\:years\:old.}$

$\rule{200}2$

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.