Sudesh is twice as old as Seema . If six years is subtracted from Seema's age and four years are added to Sudesh's age , Sudesh will be four times Seema's age . How old were they three years ago ?
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Let Seema's age be x
Let Sudesh's age be 2x
4(x-6) = 2x + 4
4x - 24= 2x + 4
4x-2x = 4+24
2x = 28
x = 28/2
x = 14
therefore,
Seema's present age is 14
Sudesh's present age is 28
three years ago,
Seema's age is 11
Sudesh's age is 25
Answered by
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Answer:
Let the age of Seema be x years.
Therefore, age of Sudesh will be 2x years.
It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]
Age of Seema = x - 6
Age of Sudesh = 2x + 4
According to Question now,
➳ 4(x - 6) = 2x + 4
➳ 4x - 24 = 2x + 4
➳ 4x - 2x = 4 + 24
➳ 2x = 28
➳ x = 28/2
➳ x = 14 years
Therefore,
Present age of Seema = x = 14 years
Present age of Sudesh = 2x = 2(14) = 28 years
So,
- Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.
- Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.
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