Question

Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four are added to Sudesh age, Sudesh will be four times Seema's age. How old were they three years ago?

Answer 1

Step-by-step explanation:

Let the age of seema is x

and the age of sudhesh is 2x

According to question

after subtracted 6 years from seema's age = (x-6)

after added 4 years in sudhesh age = (2x+4)

(2x+4) = 4(x-6)

2x+4 = 4x-24

4+24 = 4x-2x

28 = 2x

28/2 = x

14 = x

so,seema's age = 14

and sudesh age = 28

Answer 2

GIVEN :-

• Sudesh is twice as old as Seema .

• If six years is subtracted from Seema's age and four added to

        Sudesh's age , age of Sudesh  will be four times Seema's age .

TO FIND :-

• Age of Sudesh three years ago .

• Age of Seema three years ago .

SOLUTION :-

   Let ,

   Age of Seema = x

   Age of Sudhesh = 2x

    When six years is subtracted from Seema's age ,

    Age of Seema = x - 6

    When four added to Sudesh's age ,

     Age of  Sudesh = 2x + 4

      According to the question ,

            $\sf 2x+4= 4(x-6)$

         $\longrightarrow\sf 2x+4 = 4x-24 \\\\\longrightarrow 4x-2x = 24+4 \\\\\longrightarrow 2x = 28 \\\\\longrightarrow x = 14$

     

    Age of Seema = 14 years

    Age of Sudesh = 28 years

•   Age of Seema 3 years ago = 12 years

•   Age of Sudesh 3 years ago = 25 years