sudesh is twice as old as seema. if six years is subtracted from seema's age and four years added to sudesh's age, sudesh will be four times seema's age. how old were tgey tgree years ago.
Answers
Answered by
2
x = 2y
4(y-6) = 4+x
4y-24 = 4 + 2y
2y = 28
y = 14, x = 28
They were 11 and 25 three years ago.
hope this helps u...
4(y-6) = 4+x
4y-24 = 4 + 2y
2y = 28
y = 14, x = 28
They were 11 and 25 three years ago.
hope this helps u...
Answered by
9
Let seema`s present age be x yrs
sudesh`s present age = 2x yrs
subtracting 6 yrs from seema`s age = (x-6)
adding 4 yrs to sudesh`s age = 2x+4
according to the question
4(x-6) = 2x+4
⇒4x - 24 = 2x +4
⇒4x-2x = 24+4
⇒2x = 28
⇒ x = 28/2
∴ x = 14
∴present age of seema = x =14 yrs
present age of sudesh = 2x = 2×14 = 28 yrs
∴Three years ago
semma`s age = 14-3 = 11yrs
sudesh`s age = 28-3 = 25yrs
sudesh`s present age = 2x yrs
subtracting 6 yrs from seema`s age = (x-6)
adding 4 yrs to sudesh`s age = 2x+4
according to the question
4(x-6) = 2x+4
⇒4x - 24 = 2x +4
⇒4x-2x = 24+4
⇒2x = 28
⇒ x = 28/2
∴ x = 14
∴present age of seema = x =14 yrs
present age of sudesh = 2x = 2×14 = 28 yrs
∴Three years ago
semma`s age = 14-3 = 11yrs
sudesh`s age = 28-3 = 25yrs
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