sudesh is twice as old as seema if six years is subtracted from seemas age and 4 years are added to sudesh age sudesh will be four times seemas age how old were they three years ago?
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Answered by
37
Heya User,
Let Seema's age be --> 'x'
Sudesh's age ----> '2x'
--> Acc. to qn ->
---> 4( x - 6 ) = ( 2x + 4 )
=> 4x - 24 = 2x + 4
=> 2x = 28
=> x = 14
Thus, Seema's age = 14 and Sudesh's age = 28
=> Their ages '3' years ago are :-> 11 and 25 respectively √√
Let Seema's age be --> 'x'
Sudesh's age ----> '2x'
--> Acc. to qn ->
---> 4( x - 6 ) = ( 2x + 4 )
=> 4x - 24 = 2x + 4
=> 2x = 28
=> x = 14
Thus, Seema's age = 14 and Sudesh's age = 28
=> Their ages '3' years ago are :-> 11 and 25 respectively √√
sewaram:
bring
Answered by
8
let the present age of sudesh and seem a be
x and Y respectively
now acc. given condition
x= 2y
also
4 ( 6-y ) = 4+x
=24 -4y = 4+x
=24-4 = x +4y
x + 4y = 20
6y = 20
y= 20/6 = 3.3 yrs.
X= 6.6 yrs
. 3 yrs ago.
X will be 3.6 yrs old and y will be 3 months old.
am not sure with my answer
x and Y respectively
now acc. given condition
x= 2y
also
4 ( 6-y ) = 4+x
=24 -4y = 4+x
=24-4 = x +4y
x + 4y = 20
6y = 20
y= 20/6 = 3.3 yrs.
X= 6.6 yrs
. 3 yrs ago.
X will be 3.6 yrs old and y will be 3 months old.
am not sure with my answer
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