Question

Sudesh is twice as old as seema. if six years is subtracted from seema's age and four years are added to sudesh's age,sudesh will be four times as old as seema.how old were they three years ago?

Answer 1

Answer:

25 and 11

Step-by-step explanation:

Let the present ages of sudesh and seema be x and y.

As per given data,

x=2y...............(1)

x+4 =4(y-6).....(2)

using (1) In (2)

2y+4=4y-24

2y=28

y=14

x=28

Hence,

3 years ago their ages were 25 and 11

Answer 2

Answer:

Sudesh was 25 years old and seema was 11 years old

Step-by-step explanation:

Let x be the age of seema at present.

Then, Sudesh present age is 2x

From given statement,

x-6=(2x+4)/4  

4x-24=2x+4

2x=28

X=14

Seema present age =14 years  

Sudesh present age = 2x=14x2=28 years

Now, 3 years ago their ages were as given below:

Seema age= 14-3=11 years old

Sudesh age=28-3=25 years old