Question

sudesh is twice as old as seema .if six years us subtracted from seema's age and four years are added to sudesh's age, sudesh will be four times seema's age . how old were they three years ago?

Answer 1

PRESENT -

Let age of Seema = x
Then, age of Sudesh = 2x

When 6 years are subtracted from Seema's age, her age is = x-6

Four years are added to Sudesh's age = 2x+4

Now, Sudesh will be 4 times Seema's age.

Thus, 2x+4 = 4(x-6)
2x+4 = 4x-24
4x-2x = 24+4
2x = 28
x = 14

Present age of Seema = 14
Age of Seema 3 years ago = 12

Present age of Sudesh = 28
Age of Sudesh 3 years ago = 25

Answer 2

Answer:

hey dear

Step-by-step explanation:

Let age of Seema = x

Then, age of Sudesh = 2x

When 6 years are subtracted from Seema's age, her age is = x-6

Four years are added to Sudesh's age = 2x+4

Now, Sudesh will be 4 times Seema's age.

Thus, 2x+4 = 4(x-6)

2x+4 = 4x-24

4x-2x = 24+4

2x = 28

x = 14

Present age of Seema = 14

Age of Seema 3 years ago = 12

Present age of Sudesh = 28

Age of Sudesh 3 years ago = 25