Question

sudesh is twice as old as seema is if 6 years is subtracted from Seema's age and 4 years added to Sudesh's age, Sudesh age will be 4 times Sema's age. How old were they 3 years ago?

Answer 1

Let the age of Seema to be X

Then, sudesh Age = 2x

If 6 years subtracted from seema's Then....

X - 6

If 4 years added to the sudesh age

2x + 4

Then sudesh age will 4 times of Seema's age

Then the following equation

= 4(x - 6 ) = 4 + 2x

=4x - 24 = 4 + 2x

= 4x - 2x =4 + 24

= 2x = 28

= X = 28/2

= X = 14.

Then..

the seema's age = 14 years

sides age = 2 * 14

= 28 years

According to question

Three years ago..

Seema's age = 14 -3

= 11 years

Sudesh's age = 28 - 3

= 25 years.

HOPE ITS HELP YOU

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

• Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

• Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.