Question

Sudesh is twice old as seema. if six years is subtractes from seems's age and four years added to sudesh's age,sudesh will be 4 times seema's age how old were they 3 years ago

Answer 1

Let seema's present age = s
Sudesh's age = 2*s

Given: s-6 && 2s+4, then
Sudesh will be 4 times seema's age
2s + 4 = 4*(s - 6)
2s + 4 = 4s - 24
2s = 28
s = 14
2s = 28
Seema's present age = 14
Sudesh's present age = 28
3 years ago,
Seema's age = 11 years
Sudesh's age = 25 years
Hope it helps

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

• Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

• Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.