Math, asked by Theboss4989, 10 days ago

Sudha have an oil can and give 1 by 5 of the oil to her neighbour. In end of the month she found that 3 by 20 of the oil in the can was left . Find what part of the oil in the can she used in one month.

Answers

Answered by dadasahebthengil123
4

Answer:

The part of the oil in the can she used in the month is \frac{13}{10} .

10

13

.

Step-by-step explanation:

Given:

Sudha bought an oil and gave 1/5 of the oil from the can to her neighbour by the end of the month she found 30/20 of the oil in the can was left.

Now, to find the part of the oil in the can she used in the month.

So, the part of the oil she gave to her neighbour:

\frac{1}{5}

5

1

And, the part of oil she found in the can:

\frac{30}{20}

20

30

Now, to get the part of the oil in the can she used in the month by subtracting the part of the oil she gave to her neighbour from the part of oil she found in the can:

\frac{30}{20} -\frac{1}{5}

20

30

5

1

=\frac{30-4}{20}=

20

30−4

=\frac{26}{20}=

20

26

On simplifying it:

=\frac{13}{10}=

10

13

Therefore, the part of the oil in the can she used in the month is \frac{13}{10} .

10

13

.

Answered by shivanikamble369
0

Answer:

let full oil can be x

gave to the neighbour = 1/5x

left = 3/20x

x-1/5x + 3/20x

4x - 3x + 20x/20

21/20x

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