Question

sudha is twice old as her sister.five years ago,sudha's age was five times of her sister's age . Find the age of sudha?​

Answer 1

Step-by-step explanation:

Let the age of Sudha's brother be x

Sudha's age = 2x

Their ages three years ago,

\begin{gathered}Sudha = (2x - 3) \\ \\ Sudha's brother = (x - 3)\end{gathered}

Sudha=(2x−3)

Sudha

′

sbrother=(x−3)

Now,

\begin{gathered}2x - 3 = 3(x - 3) \\ \\ = > 2x - 3 = 3x - 9 \\ \\ = > x = 6\end{gathered}

2x−3=3(x−3)

=>2x−3=3x−9

=>x=6

Sudha's age = 2x = 2×6 = 12 years

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