Question

Sudha runs a square field of side 77 m, Maya runs a rectangular field with
length 150m and breadth 106 m. Who covers more distance and by how
much?
​

Answer 1

Answer:

Maya Covers more distance

By - 512- 308 = 204m

Step-by-step explanation:

Sudha Runs = 4 * 77 = 308 m

Maya Runs = 2 *(150+106) = 2*(256) = 512 m

∴ Maya Covers more distance

By - 512- 308 = 204m

Answer 2

$\sf{\huge{\star}}$ Given:-

• Sudha runs a square field of side 77 m
• Maya runs a rectangular field of length 150 m and 106 m

$\sf{\huge{\star}}$ To Find:-

Who covers more distance and by how much.

$\sf{\huge{\star}}$ Solution:-

For Sudha,

${\star}$ To find the distance covered by Sudha we need to find the perimeter of the square field.

Side of the field = 77 m

We know,

Perimeter of square = 4×side

Therefore,

$\bf{Perimeter\:of\:the\:square\:field = 4\times77}$

= $\bf{Perimeter = 308\:m}$

Therefore Sudha covered a distance of 308 m.

Now,

For Maya,

${\star}$ To find the distance covered by Maya we need to find the perimeter of the rectangular field.

Length of the field = 150 m

Breadth of the field = 106 m

We know,

Perimeter of rectangle = 2(Length + Breadth)

Therefore,

$\bf{Perimeter\:of\:rectangular\:field = 2(150 + 106 )}$

= $\bf{Perimeter = 2\times256}$

= $\bf{Perimeter = 512\:m}$

Therefore Maya covered a distance of 512 m.

From here we can clearly see that Maya covers more distance.

Difference between distance travelled by Maya and Sudha:-

$\bf{(512-308)}\:m$

= $\bf{204\:m}$

Therefore Maya covers more distance than Sudha by 204 m.

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${\huge{\star}}$ Formulas Used:-

• Perimeter of square = (4×side) units
• Perimeter of rectangle = 2(Length + Breadth) units.

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