Sudha tested the solubility of four salts X, Y, Z and T at different temperatures
and collected the following data. (Solubility refers to the amount in grams
dissolved in 100 g of water to give a saturated solution.) (3)
Answer the following questions from the table
.
(i) Which salt has the highest and lowest solubility at 323 K ?
(ii) A student prepared a saturated solution of X at 323 K and then added 25 g
water to it. What mass of X must be added to again make the solution
saturated ?
(iii) What mass of ‘T’ would be required to make saturated solution in 200 g
of water at 290 K ?
Answers
Answer:
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Explanation
1. a) The highest solubility at temperature of 323k is of salt Y
b)the lowest solubility at temperature of 323k is of salt Z
2. The amount of water added in the saturated solution of X is 25g
So , amount of salt X added to make it a saturated solution is 50g
3. As we know that solubility refers to the amount of grams dissolved in the 100 g of water to make saturated solution
so , it means that
25g of salt T is added to 100 grams of water at 290k temperature to make a saturated solution
so, amount of salt T that we add to make a saturated solution in 200g of water will Be
2 X 25g = 50g
Answer:
Explanation:
PLS MARK IT AS BRAINLIEST
1. a) The highest solubility at temperature of 323k is of salt Y
b)the lowest solubility at temperature of 323k is of salt Z
2. The amount of water added in the saturated solution of X is 25g
So , amount of salt X added to make it a saturated solution is 50g
3. As we know that solubility refers to the amount of grams dissolved in the 100 g of water to make saturated solution
so , it means that
25g of salt T is added to 100 grams of water at 290k temperature to make a saturated solution
so, amount of salt T that we add to make a saturated solution in 200g of water will Be
2 X 25g = 50g