Question

Sudhakar borrowers 22500 at 10% per annum compounded annually

if he repays 11250 at the end of first year and 12550 at the end of the second year

find the amount of loan outstanding against him at the end of the third year

this Is brainlist question​

Answer 1

amt borrowed Rs.22500

Amt. With interest 22500x110/l00

= Rs24750

Repayment = II 250

Balance-13500

Amt.with int.for 2nd, yr=13500x110/100 = 14850

Repayment-I2550

Balance = 2300

Amt.with int. 2300x110/100 = 2530

At the 3rd year he has to pay Rs.2530

Answer 2

Answer:

Step-by-step explanation:

amt borrowed Rs.22500

Amt. With interest 22500x110/l00

= Rs24750

Repayment = II 250

Balance-13500

Amt.with int.for 2nd, yr=13500x110/100 = 14850

Repayment-I2550

Balance = 2300

Amt.with int. 2300x110/100 = 2530

At the 3rd year he has to pay Rs.2530