Sudhakar borrows rs 15000 from a bank to renovate his house. he borrows the 9% p.a. simple interest over 8 years. what are his monthly repayments?
Answers
Answered by
66
The SI unit=p×r×t÷100
so it is 15000×8×9÷100=10800
so the money to be paid is 15000+10800=25800
now for the monthly repayments we have to divide it by 12 which is 2150
so it is 15000×8×9÷100=10800
so the money to be paid is 15000+10800=25800
now for the monthly repayments we have to divide it by 12 which is 2150
Answered by
216
➡HERE IS YOUR ANSWER⬇
♧♧FORMULA♧♧
Principal = P
Rate = R%
Time = T years
Interest = I
So, the relation is :
I = (P×T×R)/100
♧♧SOLUTION♧♧
Given that :
Principal (P) = Rs 15000
Time (T) = 8 years
Rate (R) = 9%
Interest (I) = (P×T×R)/100
=> I = (15000×8×9)/100
= 10800
So, Interest in 8 years = Rs 10800
Then, total money to be repaid
= Rs (15000 + 10800)
= Rs 25800
8 years = 8×12 months = 96 months
Hence, monthly repayment
= Rs (25800/96)
= Rs 268.75
⬆HOPE THIS HELPS YOU⬅
♧♧FORMULA♧♧
Principal = P
Rate = R%
Time = T years
Interest = I
So, the relation is :
I = (P×T×R)/100
♧♧SOLUTION♧♧
Given that :
Principal (P) = Rs 15000
Time (T) = 8 years
Rate (R) = 9%
Interest (I) = (P×T×R)/100
=> I = (15000×8×9)/100
= 10800
So, Interest in 8 years = Rs 10800
Then, total money to be repaid
= Rs (15000 + 10800)
= Rs 25800
8 years = 8×12 months = 96 months
Hence, monthly repayment
= Rs (25800/96)
= Rs 268.75
⬆HOPE THIS HELPS YOU⬅
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