Math, asked by aryan559, 1 year ago

sudhir lent 2000 at compound interest at 10%payable yearly while prasant lent 2000 at compound interest at 10%payable half yearly find the difference in the interest received by sudhir and prasant at the end of one year

Answers

Answered by vedant114
11
prasant
a=p(1+r/200)^2
= 2000×(105/100)^2
= 2000×11025/10000

=2205
sudir

a=p(1+r/100)^1
=2000×1.1
=2200
difference = 2205-2200
=5
Answered by PravinRatta
1

Answer:

Difference of the C.I = Rs 200 - Rs 100 = Rs 100

Step-by-step explanation:

Given,

Amount = p(1+r/200)^2

Time = 1/2 for half yearly double the time

Rate = 10%, for half yearly half the rate.

= 2000×(105/100)^1

= 2000× (21/20)

Amount = 2100

C.I =  A - P = 2100 - 2000  = Rs 100

Sudhir,

a=p(1+r/100)^1

=2000× (11/10)

=2200

C.I = A - P = 2200 - 2000  = Rs 200

Difference of the C.I = Rs 200 - Rs 100 = Rs 100

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