suhaib, while traveling to school coputes his average speed as 40km/h on returning back on the same route,their was a less traffic jam and he computes his average speed as 50km/h . Calculate his average speed,on whole trip.
Answers
Answer:
Abdul, while driving to school, computes the average speed for his trip to be 20km h
−1
. On his return trip along the same route, there is less traffic and the average speed is 30km h
−1
. What is the average speed for Abdul's trip?
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Let us assume that Abdul is travelling x kilometer distance while going to school.
Distance = Speed x Time
1)When it's average speed is 20 km/hr
x=v
1
×t
1
=20×t
1
2)When it's average speed is 30 km/hr
x=v
2
×t
2
=30×t
2
V
average
=
totaltimetaken
totaldistancetravelled
V
average
=
v
1
x
+
v
2
x
x+x
=
20
x
+
30
x
2x
=24 km h
−1
Explanation:
solved as this method
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Answer:
44.4 km/h
Explanation:
The formula used for this is called Harmonic Mean. This is the formula for average speed ONLY when the 2 distances travelled are SAME.(Applicable here as they are returning back on same route)
Where V1= the going velocity
V2=coming back velocity
V avg= 2V1*V2/V1+V2
Now substuting values
V avg = 2*40*50/40+50
= 4000/90
= 44.444.. km/h
Hope it helped