Sujata had some toffees. After distributing 60%of them if 20 toffees are still with her, how many did she give away.
Answers
Answer:
Manju had a choclate bar. She gave one-fourth to Raji, one-third to Sugatha and one-sixth to Sheela. She ate the remaining part. How many pieces of choclate did each get?
Thanks for A2A.
Suppose there are 12 pieces of Chocolate bar initially. 12, because it will give integer value to you answer.(Use L.C.M.).
Now, Raji would get 3, Sugatha would get 4, and Sheela would get 2 pieces of it. Manju would get the remaining, i.e. (12-3-4-2)=3 pieces.
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Assumption: Each got integral pieces of chocolate, which were equal in size.
So each got 1/4, 1/3, 1/6 and remaining 1/4. If these fractions were whole number pieces, then it implies that the chocolate had at least 12 pieces (LCM of 4,3,6).
So, for any multiple of 12, these people will get integral pieces of chocolates.
Thanks for the A2A. (I do not know why I answered)
If you are referring to 1/4, 1/3 and 1/6 of the entire chocolate bar, you can start by making all the fractions have a common denominator, which is 12.
1/4= 3/12
Raji would have 3/12 of the chocolate bar.
1/3= 4/12
Sugatha would have 4/12 of the chocolate bar.
1/6= 2/12
Sheela would have 2/12 of the chocolate bar.
Manju ate the remaining, so you have to find the remainder of the 12 parts.
(12-3-4-2)/12= 3/12= 1/4
Hope this helped. :)
Answer:
Question :-
Sujata had some toffees. After distributing 60%of them if 20 toffees are still with her, how many did she give away.
Given :-
Sujata had some toffees. After distributing 60%of them if 20 toffees are still with her.
Find Out :-
How many did she give away.
Solution :-
Let, the total toffees is a
According to the question or ATQ : -
➙ a = 60% × (a + 20)
➙ a = 60 /100
× (a + 20)
➙ a = 0.6 × (a + 20)
➙ a = 0.6a + 20
➙ a - 0.6a = 20
➙ 0.4a = 20
➙ a = 20/0.4
➙ a =50
Hence, number of toffees she give away :
➨ Number of toffees = 50 - 20
Step-by-step explanation:
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