Question

sujatha's present ages three fifth of her father's present age after 14 years from now the difference between the ages of 14 years find the present age​

Answer 1

Answer:

• The ages of sujata and her father are 21 and 35 years respectively

Step-by-step explanation:

Given:

• sujatha's present ages three fifth of her father's present age
• after 14 years from now the difference between the ages of 14 years

To Find:

• Find their present ages

Assumptions:

• Let the age of her father be x
• Let the age of sujata be 3/5 x

Solution:

✰ Their ages after 14 years will be,

• Sujata's age = 3/5x + 14
• Her father's age = x + 14

✰ According to the question,

$\rightarrow \tt \qquad x + 14 - \bigg (\dfrac{3x}{5} + 14\bigg) = 14$

$\rightarrow \tt \qquad x + 14 - \dfrac{3x}{5} - 14 = 14$

$\rightarrow \tt \qquad x - \dfrac{3x}{5} = 14 + 14 - 14$

$\rightarrow \tt \qquad x - \dfrac{3x}{5} = 14$

$\rightarrow \tt \qquad \dfrac{5x - 3x}{5} = 14$

$\rightarrow \tt \qquad \dfrac{2x}{5} = 14$

$\rightarrow \tt \qquad 2x = 14 \times 5$

$\rightarrow \tt \qquad 2x = 70$

$\rightarrow \tt \qquad x = \cancel\dfrac{70}{2}$

$\rightarrow \tt \qquad {\pink{\boxed{\frak{ x = 35}}}\purple\bigstar}$

✰ Now let's find the present ages,

$\nrightarrow \sf \qquad Sujata's \; father's \; age = x = 35$

$\nrightarrow \sf \qquad Sujata' \; age = \dfrac{3x}{5} = \dfrac{3(35)}{5}= 21$

Therefore:

•  The ages of sujata and her father are 21 and 35 years respectively

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