Math, asked by shreyoseeshreya5890, 7 months ago

Sujay invested an amount of rupees 16000 for two years at compound interest and received an amount of rupees 17640 on maturity. what is the rate of interest?

Answers

Answered by Anonymous
0

Answer:

good morning have a nice day

Answered by Anonymous
9

\huge\mathfrak{Answer}

 \huge \boxed{ \rm \sf \frac{a}{p} =  {1 +  \frac{r}{100} }^{n}}

 \huge \boxed{ \rm \sf \frac{17640}{16000} =  {1 +  \frac{r}{100} }^{2}}

\boxed{ \rm \sf \frac{17640}{16000} =  {1 +  \frac{r}{100} }^{2}}  \implies { \frac{21}{20} }^{2}

OR

 \sf \boxed{1 +  \frac{r}{100} } =  \frac{21}{20}  \\   \\ \therefore \sf \: rate \:  \:  = 5\%

5% is the answer

Similar questions