suley and mohamed begin walking from the same place at the same time. suley walks south at 4 mph. mohamed walks east at 3 mph. how far away from each other are they after 3 hours?
Answers
Step-by-step explanation:
3mph for 3 hrs towards East 9 km
4mph for 3 hrs towards south 12 km
by applying Pythagoras theorem we get 15km
Answer:
15 miles
Step-by-step explanation:
Refer to attachment for the diagram
It is given that Suley proceeds South and Mohamed proceeds East
So they make a Right angled triangle because South and East are perpendicular to each other (Refer the diagram)
We know that Distance covered = speed * time
So distance covered by Suley = 4 mph * 3 hours = 12 miles
So distance covered by Mohamed = 3 mph * 3 hours = 9 miles
Now the distance between Suley and Mohamed is the Hypotenuse (BC) of the Right angled Triangle
PYTHAGORAS' THEOREM : Hypotenuse² = Base² + Altitude²
=> (BC)² = (AB)² + (AC)²
=> (BC)² = (12)² + (9)²
=> (BC)² = 144 + 81
=> (BC)² = 225
=> BC = √ 225
=> BC = 15 miles
Therefore the distance between Suley and Mohamed after 3 hours was 15 miles
