Question

sulfuric acid of the concentration 90% is mixed with water to dilute to concentration 50% what will be the ratio of sulphuric acid and water that has to be mixed in this case​

Answer 1

Answer:

1:1

Step-by-step explanation:

let us consider that one lt of sulfuric acid is there

concentration is 90%

means = water is 10 %

so 900 ml is s.a and 100 ml is water

now water is added due to which concentration bcoz 50 %

in this case the 900 ml of sulfuric acid is 50 %

which means 1800 ml is total solution (bcoz 50 % = 900 then 100 % = 1800)

out of 1800 ml there is 900 ml is sulfuric acid and remaining is water (1800-900 = 900)

= 900(s.a) : 900(water)

=> 1:1