Question

sulphide ion reacts with solid sulphur
s^2-(aq)+s(s)=s^2-2(aq); k1=10
s^2-(aq)+2s(s)=s^2- 3(aq); k2=130
the equilibrium constant for the formation of s^2- 3(aq) from s^2- 2(aq) and sulphur is

Answer 1

$\huge\boxed{\red{\bold { Solution}}}$

The chemical equilibrium representing the reaction of sulfide ion with solid sulfur is,

Equilibrium 1-

s^2-(aq)+s(s)=s^2-2(aq); k1=10

Equilibrium 2-

s^2-(aq)+2s(s)=s^2- 3(aq); k2=130

Therefore, the equilibrium constant for the given equilibrium

$\frac{1}{10} \times 130$

13

Answer 2

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The chemical equilibrium representing the reaction of sulfide ion with solid sulfur is,

Equilibrium 1-

s^2-(aq)+s(s)=s^2-2(aq); k1=10

Equilibrium 2-

s^2-(aq)+2s(s)=s^2- 3(aq); k2=130

Therefore, the equilibrium constant for the given equilibrium

\frac{1}{10} \times 130

1/10 ×130

13